Daily License Questions about Ship Stability and Trim: I just think people need to have some knowledge in their heads, professional or otherwise. After 2007 our world has changed due to the advent of Smart Phones. Retaining knowledge is like being able to play a musical instrument, if you do not use it you will lose it! The questions I post with will hopefully help you keep what you already know or remind you of what you should know. William E. George
The best answer is A. Do you agree or disagree?
ReplyDeleteThe best answer is A.
ReplyDeleteSolution:
GG' free surface = 2 x length x (1/2 width)^3 / 12 x 35 cubic feet per ton x 10,000 tons
GG' free surface = 2 x 60 ft x (1/2 (30 ft))^3 / 12 x 35 cubic feet per ton x 10,000 tons
GG' free surface = 0.09 ft, so the best choice is A.
I cannot follow your numbers. Sorry, I don't see it.
ReplyDeleteLet me try it again for you, this time I will expand the math and the explanation.
ReplyDeleteFirst the free surface formula assumes a rectangular tank with a given width and length.
Second, the moment of inertial of a rectangular shape is Length x Width x Width x Width divided by 12, which is a constant for the rectangular shape and the displaced volume. In this case the displaced volume is 10,000 tons x 35 cubic feet ton = 350,000 cubic feet.
Third, in this problem the original tank has been subdivided down its centerline so there are now two smaller tanks with a width of 15 feet and a length of 60 feet. This is why I started my calculation with 2 x.
So lets put it all together doing one of the two tanks first then simply doubling the answer:
FS = LBBB/12Displaced Volume
FS = 60ft(15ft)(15ft)(15ft) / 12 (350,000) cubic feet = 0.48 ft for one tank
Now if we double it for two tanks we get 0.098 ft and Answer A. = 0.1 foot !
I hope this makes the answer easier to see.
Thanks...Much better. Now I see what you did.
DeleteOk A, got it
ReplyDelete