A cargo of 30 tons is to be loaded on deck 30 feet from the ship's centerline. The ship's displacement
including the 30 tons cargo will be 9,000 tons and the GM will be 5 feet. The list of the vessel after loading this cargo will be __________.
A. 1.14° B. 2.05° C. 2.31° D. 3.40°
including the 30 tons cargo will be 9,000 tons and the GM will be 5 feet. The list of the vessel after loading this cargo will be __________.
A. 1.14° B. 2.05° C. 2.31° D. 3.40°
Use the Inclining Experiment Formula for this one.
ReplyDeleteWeight = 30 tons
Distance from Centerline = 30 feet
Displacement = 9000 tons
Gm = 5 feet
tan (angle of list) = Weight x Distance / Displacement x GM
tangent (angle of list ) = 30 x 30/9000 x 5 = 0.02
angle of list = arc tangent (0.02) = 1.145 degrees
The best answer is Choice A.
Check this link out to see how you get arc tangent or inverse tangent on a calculator!
ReplyDeletehttps://www.youtube.com/watch?v=oHwjOISl63I
Pg. 119 Practical Applications:
ReplyDeletetanθ = (w*d) / (GM*Δ)
(30*30)/(5*9000)=0.02
2nd tan =1.14576 or 1.15˚
ANS=ALPHA is closest