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Daily Question for March 23, 2018

What is the reduction in metacentric height due to free surface when a tank 60 ft. wide and 60 ft. long is partially filled with saltwater? (The vessel's displacement is 10,000 tons.)

A. 3.00 feet   B. 3.09 feet   C. 3.15 feet   D. 3.20 feet

Comments

  1. UnknownMarch 23, 2018 at 5:23 PM

    (l * b3)/(420 * Δ)
    (60 x 60 cubed)/(420 x 10000)=3.0857

    ANS: Charley

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  2. UnknownMarch 23, 2018 at 5:26 PM

    the tank is filled with seawater so I didn't add the ratio.
    (r*l*b3)/(420*Δ)

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  3. Friends of STABILITY AND TRIM FOR THE SHIP'S OFFICERMarch 23, 2018 at 5:55 PM

    I agree. "C."is the best answer.

    FYI,, 420 is a constant = 12 x 35 cuft/LT. It is a nice short cut if you need to multiply 12 x 35 x displacement in LT like in the FS formula.

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  4. UnknownMarch 28, 2018 at 2:54 AM

    The result I have is 3.0857 and it is closer to answer "B" 3.09.

    ReplyDelete

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