Determine the free surface correction for a fuel oil tank 30 ft. long by 40 ft. wide by 15 ft. deep, with a free surface constant of 3794. The vessel is displacing 7,000 tons in saltwater.
A, 0.35 foot B. 0.54 foot C. 0.65 foot D. 1.38 feet
A, 0.35 foot B. 0.54 foot C. 0.65 foot D. 1.38 feet
All you do in this case is to divide the Free surface constant by the displacement!
ReplyDelete3794/7000 = 0.542 foot, sot he best answer is B.