On a vessel of 15,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water in the tank tops. The hold is 50 feet long and 60 feet wide. The reduction in metacentric height is __________.
A. 1.54 feet
B. 1.59 feet
C. 1.63 feet
D. 1.71 feet
A. 1.54 feet
B. 1.59 feet
C. 1.63 feet
D. 1.71 feet
LB^3/12(displaced volume)
ReplyDelete= 50 x 60 x 60 x 60 / 12 (35 x 15000)
= 1.71 ft
The best answer is D.