Skip to main content

Daily Question for April 20. 2018

Your ship of 12,000 tons displacement has a center of gravity of 21.5 feet above the keel. You run aground and estimate the weight aground is 2500 tons. The virtual rise in the center of gravity is __________.

A. 1.26 feet   B. 3.80 feet   C. 4.80 feet   D. 5.66 feet

Comments

  1. Frederico ManchadoApril 20, 2018 at 4:16 AM

    GG' = (w x KG) / (W - w)

    GG' = (2500tons x 21,5 ft) / ((12000 - 2500)tons)

    GG' = 5,65789 ft

    D. is the best answer

    ReplyDelete

Post a Comment