A ship is inclined by moving a weight of 30 tons a distance of 30 ft. from the centerline. A 28-foot
pendulum shows a deflection of 12 inches. Displacement including weight moved is 4,000 tons. KM is 27.64 feet. What is the KG?
A. 21.34 feet B. 22.06 feet C. 22.76 feet D. 23.21 feet
pendulum shows a deflection of 12 inches. Displacement including weight moved is 4,000 tons. KM is 27.64 feet. What is the KG?
A. 21.34 feet B. 22.06 feet C. 22.76 feet D. 23.21 feet
sinθ = 12inches / ((12 x 28)inches) = 1/28
ReplyDeleteθ=arcsin(1/28)
GM = GG' / tgθ
GG' = w x d / W = 30tons x 30ft / 4000tons = 9/40 ft
GM = 9/40 ft / tg(arcsin(1/28)) = 6.29598 ft
KG = KM - GM = 27.64ft - 6.29598ft = 21.34404ft
A. is the best answer